Top persons sorted by score (Another of the Prime Pages' resources)

The Prover-Account Top 20
Persons by: number score normalized score
Programs by: number score normalized score
Projects by: number score normalized score

At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.

Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes. Based on the usual estimates we score the top persons, provers and projects by adding ‎(log n)3 log log n‎ for each of their primes n. Click on 'score' to see these lists.

Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.

rank person primes score 588 Ed Goforth 1.5 44.0274 589 Jack Clark 1 44.0270 590 Frédéric Mahé 2 44.0257 591 Bartosz Michałowski 1 44.0211 592 Duboi Si 1 44.0184 593 Dennis Chi 1 44.0169 594 Jay Berg 1 44.0168 595 Peter van Hoof 1 44.0109 596 Robert M.C. van Weers 1 44.0106 597 Christopher Preusch 1 44.0102 598 Ondrej Hajek 1 44.0097 599 Jussi Heino 2 44.0096 600 Anthony Storch 1 43.9981 601 Phillip Butler 1 43.9849 602 Jason Gledhill 2 43.9808 603 Michael Ruber 1 43.9802 604 Joel Armengaud 1 43.9762 605 Alexander Savchenko 1 43.9758 606 Guido Stolz 1 43.9706 607 Maik Gruenewald 2 43.9647

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#### Notes:

Score for Primes

To find the score for a person, program or project's primes, we give each prime n the score (log n)3 log log n; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets one-third of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)

How did we settle on (log n)3 log log n? For most of the primes on the list the primality testing algorithms take roughly O(log(n)) steps where the steps each take a set number of multiplications. FFT multiplications take about

O( log n . log log n . log log log n )
operations. However, for practical purposes the O(log log log n) is a constant for this range number (it is the precision of numbers used during the FFT, 64 bits suffices for numbers under about 2,000,000 digits).

Next, by the prime number theorem, the number of integers we must test before finding a prime the size of n is O(log n) (only the constant is effected by prescreening using trial division).  So to get a rough estimate of the amount of time to find a prime the size of n, we just multiply these together and we get

O( (log n)3 log log n ).
Finally, for convenience when we add these scores, we take the log of the result.  This is because log n is roughly 2.3 times the number of digits in the prime n, so (log n)3 is quite large for many of the primes on the list. (The number of decimal digits in n is floor((log n)/(log 10)+1)).