Top persons sorted by score (Another of the Prime Pages' resources)

The Prover-Account Top 20
Persons by: number score normalized score
Programs by: number score normalized score
Projects by: number score normalized score

At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.

Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes. Based on the usual estimates we score the top persons, provers and projects by adding ‎(log n)3 log log n‎ for each of their primes n. Click on 'score' to see these lists.

Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.

rank person primes score 852 Brad Johnston 1 43.3837 853 David Slowinski 3.5 43.3834 854 Jelle Baris 1 43.3831 855 Matt Zilmer 1 43.3829 856 Alexis Kravtchenko 1 43.3823 857 Zbigniew Lewandowski 1 43.3808 858 Paul Gage 1.5 43.3764 859 Richard Kapek 1 43.3729 860 Taishi Demizu 1 43.3702 861 Maurice Vanden Eeckhoudt 1 43.3690 862 Fausto Falcone 1 43.3665 863 Joe Smith 1 43.3648 864 Henning Busacker 1 43.3608 865 Sean Faith 1 43.3598 866 Claude Dulaurens 1 43.3419 867 Magnus Mischel 1 43.3392 868 Stephen Hutchinson 1 43.3345 869 Andrew Olson 1 43.3263 870 Karl Pohorily 1 43.3240 871 Erik Reder 1 43.3220

move up list
move down list

#### Notes:

Score for Primes

To find the score for a person, program or project's primes, we give each prime n the score (log n)3 log log n; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets one-third of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)

How did we settle on (log n)3 log log n? For most of the primes on the list the primality testing algorithms take roughly O(log(n)) steps where the steps each take a set number of multiplications. FFT multiplications take about

O( log n . log log n . log log log n )
operations. However, for practical purposes the O(log log log n) is a constant for this range number (it is the precision of numbers used during the FFT, 64 bits suffices for numbers under about 2,000,000 digits).

Next, by the prime number theorem, the number of integers we must test before finding a prime the size of n is O(log n) (only the constant is effected by prescreening using trial division).  So to get a rough estimate of the amount of time to find a prime the size of n, we just multiply these together and we get

O( (log n)3 log log n ).
Finally, for convenience when we add these scores, we take the log of the result.  This is because log n is roughly 2.3 times the number of digits in the prime n, so (log n)3 is quite large for many of the primes on the list. (The number of decimal digits in n is floor((log n)/(log 10)+1)).