
The hardware and software on this system was updated September 4th.
Please let me know of any problem you encounter.
< caldwell@utm.edu>
At this site we keep several lists of primes, most notably the list of the 5,000 largest known primes. Who found the most of these record primes? We keep separate counts for persons, projects and programs. To see these lists click on 'number' to the right.
Clearly one 100,000,000 digit prime is much harder to discover than quite a few 100,000 digit primes. Based on the usual estimates we score the top persons, provers and projects by adding (log n)^{3} log log n for each of their primes n. Click on 'score' to see these lists.
Finally, to make sense of the score values, we normalize them by dividing by the current score of the 5000th prime. See these by clicking on 'normalized score' in the table on the right.
Notes:
 Score for Primes
To find the score for a person, program or project's primes, we give each prime n the score (log n)^{3} log log n; and then find the sum of the scores of their primes. For persons (and for projects), if three go together to find the prime, each gets onethird of the score. Finally we take the log of the resulting sum to narrow the range of the resulting scores. (Throughout this page log is the natural logarithm.)
How did we settle on
(log n)^{3} log log n?
For most of the primes on the list the primality testing algorithms take
roughly O(log(n)) steps
where the steps each take a set number of multiplications. FFT
multiplications take about
O( log n ^{.} log log n ^{.} log log log n )
operations. However, for practical purposes the
O(log log log n) is a constant for this range number
(it is the precision of numbers used during the FFT, 64 bits suffices for
numbers under about 2,000,000 digits).
Next, by the prime
number theorem, the number of integers we must test before finding a
prime the size of n is O(log n) (only the constant is
effected by prescreening using trial division). So to get a rough
estimate of the amount of time to find a prime the size of n, we
just multiply these together and we get
O( (log n)^{3} log log n ).
Finally, for convenience when we add these scores, we take the log of the
result. This is because log n is roughly 2.3 times the
number of digits in the prime n, so (log n)^{3}
is quite large for many of the primes on the list. (The number of
decimal digits in n is floor((log n)/(log 10)+1)).
