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25505418241 = 1021 * 3061 * 8161, is the smaller of the smallest pair of 2 consecutive Carmichael numbers which are both n-brilliant for any n, since the next Carmichael number is: 25509692041 = 1429 * 3571 * 4999. Note that the larger of the pair (both of which truncate to the prime 41) has the greatest possible 4-digit sum of prime factors, as: 1429 + 3571 + 4999 = 9999 = 3^2 * 11 * 101, where 3, 11, and 101 are all palindromic primes. [Carmichael]

 

  Submitted: 2004-11-03 18:51:06;   Last Modified: 2008-01-30 11:28:00.



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