|
|
|
Curios:
Curios Search:
Participate: |
Single Curio View: (Seek other curios for this number) 131 = (1^0+3^0+1^0) + (1^1+3^1+1^1) + (1^2+3^2+1^2) + (1^3+3^3+1^3) + (1^4+3^4+1^4). Note that the summands are all primes. [Silva]
Submitted: 2008-01-13 13:12:24; Last Modified: 2008-01-30 11:28:00.
Prime Curios! © 1999-2012 (all rights
reserved)
|