|
|
|
Curios:
Curios Search:
Participate: |
Single Curio View: (Seek other curios for this number) Let p(i) be the ith prime. Then p(k)# < k2Ck = (k2)!/(k!*(k2-k)!) for 2 < k < 1794. But p(k)# > (k2)!/(k!*(k2-k)!) for k > 1794. What is this key prime p(k)? 15359. [Caldwell]
Submitted: 2008-03-12 20:29:25; Last Modified: 2008-07-10 13:14:33.
Prime Curios! © 1999-2012 (all rights
reserved)
|