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Proving the Riemann Hypothesis is equivalent to showing
floor(H(n)+eH(n))*log(H(n)) > σ(n),
where H(n) = 1 + 1/2 + 1/3 + ... + 1/n, and σ(n) is the sum of the divisors of n. For example, when n = 17, the two sides differ by 23. [Caldwell]

 

  Submitted: 2008-07-25 13:13:29;   Last Modified: 2008-07-25 17:53:01.



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