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(1 + 2 + 3 + ... + 131073)/(F0*F4) = 2*F1*F2*F3 + 1 is prime, where Fn denotes the nth Fermat number. [Wesolowski]

 

  Submitted: 2009-05-14 14:28:55;   Last Modified: 2011-01-19 15:23:40.



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