Prime Curios!: 127

127
(another Prime Pages' Curiosity)

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127 = 10^2+3^3 = gives 127 = 2^2*5^2+3^3 where p1 appears three times, p2 twice and p3 once. 127 = 2^6+3^3+6^2 (palindromic) = p31 = pp11 = ppp5 = pppp3 = ppppp2 = pppppp1. 127 is the prime for which ((P1+...+pn)/pn) decreases for the first time. [Marot]

Submitted: 2009-05-18 03:46:21; Last Modified: 2009-05-18 07:02:05.