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Single Curio View: (Seek other curios for this number) 8441, whose digits are 2^3, 2^2, 2^0, is the sum of the cubes of 3 = (8+4)/(4*1) consecutive primes 11^3 + 13^3 + 17^3. [Post]
Submitted: 2009-08-18 00:00:12; Last Modified: 2009-08-18 06:01:56.
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