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Given any even digit E and any odd digit O, integer D, and 0 < R < 2D, there is exactly one number D digits in length containing only the digits E and O which leaves remainder R when divided by 2D. [Rupinski]

 

  Submitted: 2003-02-11 17:34:11;   Last Modified: 2008-07-21 11:35:58.



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