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(just those submitted by Wesolowski)
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+ 1/(2*ln(2)3/2) + 1/(3*ln(3)3/2) + 1/(4*ln(4)3/2) + ... + 1/(n*ln(n)3/2) ~ 1/ln(2)2 + 1/ln(3)3 + 1/ln(5)5 + ... + 1/ln(p)p ~ 2.93767..., as n and p approaches infinity. [Wesolowski]




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