 |
15359 (another Prime Pages' Curiosity) |
|
|
Curios:
Curios Search:
Participate:
|
Let p(i) be the ith prime. Then p(k)# < k2Ck = (k2)!/(k!*(k2-k)!) for
2 < k < 1794. But p(k)# > (k2)!/(k!*(k2-k)!) for k >
1794. What is this key prime p(k)? 15359. [Caldwell]
To link to this page use http://primes.utm.edu/curios/page.php?number_id=7638
Prime Curios! © 1999-2009 (all rights
reserved)
|