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43691 (another Prime Pages' Curiosity) |
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(1 + 2 + 3 + ... + 131073)/(F0*F4) =
2*F1*F2*F3 + 1 is prime,
where Fn denotes the nth Fermat number. This
prime starts a Cunningham chain of length 3 (1st kind). [Wesolowski]
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