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At this site we maintain a list of the 5000 Largest Known Primes which is updated hourly. This list is the most important databases at The Prime Pages: a collection of research, records and results all about prime numbers. This page summarizes our information about one of these primes. This prime's information:
| field (help) | value |
| Description: | 1195203 · 21195203-1 |
| Verification status (*): | Proven |
| Official Comment: | Woodall |
| Proof-code(s): (*): | L124 : Rodenkirch, MultiSieve, LLR |
| Decimal Digits: | 359799 (log10 is 359798.031349252) |
| Rank (*): | 205 (digit rank is 1) |
| Entrance Rank (*): | 63 |
| Currently on list? (*): | short |
| Submitted: | 7/11/2005 07:36:21 CDT |
| Last modified: | 7/12/2005 00:08:06 CDT |
| Database id: | 75032 |
| Status Flags: | none |
| Score (*): | 43.494 (normalized score 17.7761) |
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Archival tags:
There are certain forms classed as
archivable: these prime may (at times)
remain on this list even if they do not make
the Top 5000 proper. Such primes are tracked with archival
tags.
- Woodall Primes (archivable *)
- Prime on list: yes, rank 6
Subcategory: "Woodall Primes"
(archival tag id 187094, tag last modified 2009-02-12 20:01:30)
Verification data:
The Top 5000 Primes is a list for proven primes only. In order to maintain the
integrity of this list, we seek to verify the primality of all submissions.
We are currently unable to check all proofs (ECPP, KP, ...), but we will at least trial
divide and PRP
check every entry before it is included in the list.
| field | value |
| prime_id | 75032 |
| person_id | 9 |
| machine | Linux P4 2.8GHz |
| what | prime |
| notes | Command: /home/caldwell/client/llr.pl 1195203*2^1195203-1 2>&1 Starting Lucas Lehmer Riesel prime test of 1195203*2^1195203-1 V1 = 3 ; Computing U0... Done Computing U0. Starting Lucas-Lehmer loop... 1195203*2^1195203-1 is prime! Time : 20429.340 sec.
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| modified | 2005-07-15 09:51:51 |
| created | 2005-07-11 07:53:01 |
| id | 80129 |
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Query times: 0.0002 seconds to select prime, 0.0003 seconds to seek comments.
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