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+ Let p(i) be the ith prime. Then p(k)# < k2Ck = (k2)!/(k!*(k2-k)!) for 2 < k < 1794. But p(k)# > (k2)!/(k!*(k2-k)!) for k > 1794. What is this key prime p(k)? 15359. [Caldwell]

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