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       405 3453646720 8410989152 5651445494 5322730370 5227281393 9092607711
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The start of 8 consecutive primes ending in 11: 405345364672084109891525651445494532273037052272813939092607711 + n, for n = 0, 100, 300, 400, 600, 700, 900, 1000. Divisibility by 3 makes 1000 the smallest possible span for 8 primes ending in the same two digits. [Andersen]

 

  Submitted: 2009-09-19 21:28:33;   Last Modified: 2009-09-19 21:38:47.



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