Curios:
Curios Search:
Participate:
|
153 is equal to the alternating sum and difference of the squares of the integers from 1 to 153's largest prime factor, 17. [Cramer]
(153) = (15) x 3!. [Gupta]
153 is the sum of all the integers from 1 to 17 (which is prime).
2^2 * 7 + 5^3 = 1*1*1 + 5*5*5 + 3*3*3 = (1+5+3) * 17 = 1! +
2! + 3! + 4! + 5! = N. Note: (a) representation with first
four primes only, (b1) sum of first three odd cubes and
bases are digits of N, divisible by three primes (counted
with multiplicity), (b2) Harshad-Niven-Kaprekar number,
i.e., divisible by the sum of its digits, (c) sum of first
five faculties. [Zschorn]
|